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X^2-0.45X+0.0045=0
a = 1; b = -0.45; c = +0.0045;
Δ = b2-4ac
Δ = -0.452-4·1·0.0045
Δ = 0.1845
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.45)-\sqrt{0.1845}}{2*1}=\frac{0.45-\sqrt{0.1845}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.45)+\sqrt{0.1845}}{2*1}=\frac{0.45+\sqrt{0.1845}}{2} $
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